Statement-1: The path of a charged particle m | vedclass

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(D) The magnetic force on a charged particle is given by $\vec{F} = q(\vec{v} 	imes \vec{B})$,which has a magnitude $F = qvB \sin 	heta$,where $	he

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Statement-$1$ is true,Statement-$2$ is true; Statement-$2$ is the correct explanation of Statement-$1$.

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(D) The magnetic force on a charged particle is given by $\vec{F} = q(\vec{v} 	imes \vec{B})$,which has a magnitude $F = qvB \sin 	heta$,where $	heta$ is the angle between the velocity vector $\vec{v}$ and the magnetic field vector $\vec{B}$.If $	heta = 0^\circ$ or $180^\circ$,the magnetic force $F$ becomes $0$. In this case,the particle continues to move in a straight line with constant velocity.Thus,Statement-$1$ is true.The path of the charged particle is determined by the angle $	heta$ between the velocity $\vec{v}$ and the magnetic field $\vec{B}$. If $	heta = 0^\circ$ or $180^\circ$,the path is a straight line; if $	heta = 90^\circ$,the path is circular; and for other angles,the path is helical.Therefore,Statement-$2$ is true and it correctly explains why the path can be a straight line as mentioned in Statement-$1$.

Statement-$1$: The path of a charged particle may be a straight line in a uniform magnetic field.
Statement-$2$: The path of a charged particle is decided by the angle between its velocity and the magnetic field acting on it.

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Statement-$1$: The path of a charged particle may be a straight line in a uniform magnetic field.Statement-$2$: The path of a charged particle is decided by the angle between its velocity and the magnetic field acting on it.